In fig, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. then

A villager Itwarri has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the corners to construct a Health Centre. Itwarri agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented

ABCD is a trapezium with AB∥DC. A line parallel to AC intersects AB at X and BC at Y. then ar(△ADX)=ar(△ACY)

In Fig, APparallelBQparallelCR. Prove that ar(AQC)=ar(PBR). then both the quadrilaterals ABCD and DCPR are trapeziums.

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(△AOD)=ar(△BOC). then ABCD is a trapezium

In fig, ar(DRC)=ar(DPC) and ar(BDP)=ar(ARC). then both the quadrilaterals ABCD and DCPR are trapeziums.

In ABCD is a quadrilateral and BE∥AC and also BE meets DC produced at E. Show that area of △ADE is equal to the area of the quadrilateral ABCD.

ABCD is quadrilateral and BD is one of its diagonals; as shown in the figure. Find the area of quadrilateral ABCD.

In which ratio the line segment joining the mid-points of a pair of opposite sides of a parallelogram divides into two parallelograms?

In figure, ABCD is a parallelogram AE⊥DC and CF⊥AD. If AB=16 cm, AE=8 cm and CF=10 cm find AD.

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB (produced) at Q and then parallelogram PBQR is completed (figure). Find ar(ABCD) : ar(PBQR).

True or False, PQRS is a parallelogram whose area is 180 cm 2 and A is any point on the diagonal QS. The area of △ASR=90 cm² .

D and E are points on sides AB and AC respectively of △ABC such that ar(△BCD)= ar(△BCE). then DE∣∣BC

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. then the perimeter of the parallelogram is greater than that of the rectangle.

In Fig, D and E are two points on BC such that BD=DE=EC. then ar(ABD) = ar(ADE) = ar(AEC).