The correct answer is:

â‚¹1925

Therefore, if

$2Ï€=220$

Or, $2Ã— $\displaystyle \dfrac{22}{7}$â€‹Ã—=220$

$Â or,ÂÃ—Ã—22$

i.e., radius of the field is $35Âm$.

Therefore, area of the field $=Ï€rÂ²= $\displaystyle \dfrac{22}{7}$Ã—35Ã—35ÂÂ²=22Ã—5Ã—35ÂÂ²$

Now, cost of ploughing $1ÂmÂ²$Â of the field $=â‚¹0.50$

So, total cost of ploughing the field $=â‚¹22Ã—5Ã—35Ã—0.50=â‚¹1925$

â‚¹1925

**Explanation:**

Length of the fence (in meters) = $\displaystyle \dfrac{Total cost}{Rate}$ = $\displaystyle \dfrac{5820}{24}$ = 220 So, circumference of the the fieldÂ = 220 mTherefore, if

*r*meters is the radius of the field , then$2Ï€=220$

Or, $2Ã— $\displaystyle \dfrac{22}{7}$â€‹Ã—=220$

$Â or,ÂÃ—Ã—22$

i.e., radius of the field is $35Âm$.

Therefore, area of the field $=Ï€rÂ²= $\displaystyle \dfrac{22}{7}$Ã—35Ã—35ÂÂ²=22Ã—5Ã—35ÂÂ²$

Now, cost of ploughing $1ÂmÂ²$Â of the field $=â‚¹0.50$

So, total cost of ploughing the field $=â‚¹22Ã—5Ã—35Ã—0.50=â‚¹1925$